remove-nodes-from-linked-list

Remove Nodes From Linked List

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removeNodes

You are given the <code>head</code> of a linked list.

Remove every node which has a node with a strictly greater value anywhere to the right side of it.

Return the <code>head</code> of the modified linked list.

&nbsp;
Example 1:
<img alt="" src="https://assets.leetcode.com/uploads/2022/10/02/drawio.png" style="width: 631px; height: 51px;" />
<pre>
Input: head = [5,2,13,3,8]
Output: [13,8]
Explanation: The nodes that should be removed are 5, 2 and 3.
- Node 13 is to the right of node 5.
- Node 13 is to the right of node 2.
- Node 8 is to the right of node 3.
</pre>

Example 2:

<pre>
Input: head = [1,1,1,1]
Output: [1,1,1,1]
Explanation: Every node has value 1, so no nodes are removed.
</pre>

&nbsp;
Constraints:

<ul>
	<li>The number of the nodes in the given list is in the range <code>[1, 105]</code>.</li>
	<li><code>1 &lt;= Node.val &lt;= 105</code></li>
</ul>

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