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Description
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Editorial
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Solutions
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Submissions
Medium

You are given a string s consisting of '(' and ')', and an integer k.

A string is k-balanced if it is exactly k consecutive '(' followed by k consecutive ')', i.e., '(' * k + ')' * k.

For example, if k = 3, k-balanced is "((()))".

You must repeatedly remove all non-overlapping k-balanced from s, and then join the remaining parts. Continue this process until no k-balanced substring exists.

Return the final string after all possible removals.

 

​​​​​​​Example 1:

Input: s = "(())", k = 1

Output: ""

Explanation:

k-balanced substring is "()"

StepCurrent sk-balancedResult s
1(())(())()
2()()Empty

Thus, the final string is "".

Example 2:

Input: s = "(()(", k = 1

Output: "(("

Explanation:

k-balanced substring is "()"

StepCurrent sk-balancedResult s
1(()((()(((
2((-((

Thus, the final string is "((".

Example 3:

Input: s = "((()))()()()", k = 3

Output: "()()()"

Explanation:

k-balanced substring is "((()))"

StepCurrent sk-balancedResult s
1((()))()()()((()))()()()()()()
2()()()-()()()

Thus, the final string is "()()()".

 

Constraints:

  • 2 <= s.length <= 105
  • s consists only of '(' and ')'.
  • 1 <= k <= s.length / 2
 
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Code
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Test Result