most-beautiful-item-for-each-query

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Algorithms

You are given a 2D integer array <code>items</code> where <code>items[i] = [pricei, beautyi]</code> denotes the price and beauty of an item respectively.

You are also given a 0-indexed integer array <code>queries</code>. For each <code>queries[j]</code>, you want to determine the maximum beauty of an item whose price is less than or equal to <code>queries[j]</code>. If no such item exists, then the answer to this query is <code>0</code>.

Return an array <code>answer</code> of the same length as <code>queries</code> where <code>answer[j]</code> is the answer to the <code>jth</code> query.

&nbsp;
Example 1:

<pre>
Input: items = [[1,2],[3,2],[2,4],[5,6],[3,5]], queries = [1,2,3,4,5,6]
Output: [2,4,5,5,6,6]
Explanation:
- For queries[0]=1, [1,2] is the only item which has price &lt;= 1. Hence, the answer for this query is 2.
- For queries[1]=2, the items which can be considered are [1,2] and [2,4]. 
 The maximum beauty among them is 4.
- For queries[2]=3 and queries[3]=4, the items which can be considered are [1,2], [3,2], [2,4], and [3,5].
 The maximum beauty among them is 5.
- For queries[4]=5 and queries[5]=6, all items can be considered.
 Hence, the answer for them is the maximum beauty of all items, i.e., 6.
</pre>

Example 2:

<pre>
Input: items = [[1,2],[1,2],[1,3],[1,4]], queries = [1]
Output: [4]
Explanation: 
The price of every item is equal to 1, so we choose the item with the maximum beauty 4. 
Note that multiple items can have the same price and/or beauty. 
</pre>

Example 3:

<pre>
Input: items = [[10,1000]], queries = [5]
Output: [0]
Explanation:
No item has a price less than or equal to 5, so no item can be chosen.
Hence, the answer to the query is 0.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= items.length, queries.length &lt;= 105</code></li>
	<li><code>items[i].length == 2</code></li>
	<li><code>1 &lt;= pricei, beautyi, queries[j] &lt;= 109</code></li>
</ul>