minimum-bit-flips-to-convert-number

Minimum Bit Flips to Convert Number

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minBitFlips

A bit flip of a number <code>x</code> is choosing a bit in the binary representation of <code>x</code> and flipping it from either <code>0</code> to <code>1</code> or <code>1</code> to <code>0</code>.

<ul>
	<li>For example, for <code>x = 7</code>, the binary representation is <code>111</code> and we may choose any bit (including any leading zeros not shown) and flip it. We can flip the first bit from the right to get <code>110</code>, flip the second bit from the right to get <code>101</code>, flip the fifth bit from the right (a leading zero) to get <code>10111</code>, etc.</li>
</ul>

Given two integers <code>start</code> and <code>goal</code>, return the minimum number of bit flips to convert <code>start</code> to <code>goal</code>.

&nbsp;
Example 1:

<pre>
Input: start = 10, goal = 7
Output: 3
Explanation: The binary representation of 10 and 7 are 1010 and 0111 respectively. We can convert 10 to 7 in 3 steps:
- Flip the first bit from the right: 1010 -&gt; 1011.
- Flip the third bit from the right: 1011 -&gt; 1111.
- Flip the fourth bit from the right: 1111 -&gt; 0111.
It can be shown we cannot convert 10 to 7 in less than 3 steps. Hence, we return 3.</pre>

Example 2:

<pre>
Input: start = 3, goal = 4
Output: 3
Explanation: The binary representation of 3 and 4 are 011 and 100 respectively. We can convert 3 to 4 in 3 steps:
- Flip the first bit from the right: 011 -&gt; 010.
- Flip the second bit from the right: 010 -&gt; 000.
- Flip the third bit from the right: 000 -&gt; 100.
It can be shown we cannot convert 3 to 4 in less than 3 steps. Hence, we return 3.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>0 &lt;= start, goal &lt;= 109</code></li>
</ul>

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