maximum-xor-after-operations

Maximum XOR After Operations 

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maximumXOR

You are given a 0-indexed integer array <code>nums</code>. In one operation, select any non-negative integer <code>x</code> and an index <code>i</code>, then update <code>nums[i]</code> to be equal to <code>nums[i] AND (nums[i] XOR x)</code>.

Note that <code>AND</code> is the bitwise AND operation and <code>XOR</code> is the bitwise XOR operation.

Return the maximum possible bitwise XOR of all elements of <code>nums</code> after applying the operation any number of times.

&nbsp;
Example 1:

<pre>
Input: nums = [3,2,4,6]
Output: 7
Explanation: Apply the operation with x = 4 and i = 3, num[3] = 6 AND (6 XOR 4) = 6 AND 2 = 2.
Now, nums = [3, 2, 4, 2] and the bitwise XOR of all the elements = 3 XOR 2 XOR 4 XOR 2 = 7.
It can be shown that 7 is the maximum possible bitwise XOR.
Note that other operations may be used to achieve a bitwise XOR of 7.</pre>

Example 2:

<pre>
Input: nums = [1,2,3,9,2]
Output: 11
Explanation: Apply the operation zero times.
The bitwise XOR of all the elements = 1 XOR 2 XOR 3 XOR 9 XOR 2 = 11.
It can be shown that 11 is the maximum possible bitwise XOR.</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= nums.length &lt;= 105</code></li>
	<li><code>0 &lt;= nums[i] &lt;= 108</code></li>
</ul>

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