max-sum-of-a-pair-with-equal-sum-of-digits

Max Sum of a Pair With Equal Sum of Digits

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maximumSum

You are given a 0-indexed array <code>nums</code> consisting of positive integers. You can choose two indices <code>i</code> and <code>j</code>, such that <code>i != j</code>, and the sum of digits of the number <code>nums[i]</code> is equal to that of <code>nums[j]</code>.

Return the maximum value of <code>nums[i] + nums[j]</code> that you can obtain over all possible indices <code>i</code> and <code>j</code> that satisfy the conditions.

&nbsp;
Example 1:

<pre>
Input: nums = [18,43,36,13,7]
Output: 54
Explanation: The pairs (i, j) that satisfy the conditions are:
- (0, 2), both numbers have a sum of digits equal to 9, and their sum is 18 + 36 = 54.
- (1, 4), both numbers have a sum of digits equal to 7, and their sum is 43 + 7 = 50.
So the maximum sum that we can obtain is 54.
</pre>

Example 2:

<pre>
Input: nums = [10,12,19,14]
Output: -1
Explanation: There are no two numbers that satisfy the conditions, so we return -1.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= nums.length &lt;= 105</code></li>
	<li><code>1 &lt;= nums[i] &lt;= 109</code></li>
</ul>

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