kth-largest-element-in-a-stream

Kth Largest Element in a Stream

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Design a class to find the <code>kth</code> largest element in a stream. Note that it is the <code>kth</code> largest element in the sorted order, not the <code>kth</code> distinct element.

Implement <code>KthLargest</code> class:

<ul>
	<li><code>KthLargest(int k, int[] nums)</code> Initializes the object with the integer <code>k</code> and the stream of integers <code>nums</code>.</li>
	<li><code>int add(int val)</code> Appends the integer <code>val</code> to the stream and returns the element representing the <code>kth</code> largest element in the stream.</li>
</ul>

&nbsp;
Example 1:

<pre>
Input
[&quot;KthLargest&quot;, &quot;add&quot;, &quot;add&quot;, &quot;add&quot;, &quot;add&quot;, &quot;add&quot;]
[[3, [4, 5, 8, 2]], [3], [5], [10], [9], [4]]
Output
[null, 4, 5, 5, 8, 8]

Explanation
KthLargest kthLargest = new KthLargest(3, [4, 5, 8, 2]);
kthLargest.add(3); // return 4
kthLargest.add(5); // return 5
kthLargest.add(10); // return 5
kthLargest.add(9); // return 8
kthLargest.add(4); // return 8
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= k &lt;= 104</code></li>
	<li><code>0 &lt;= nums.length &lt;= 104</code></li>
	<li><code>-104 &lt;= nums[i] &lt;= 104</code></li>
	<li><code>-104 &lt;= val &lt;= 104</code></li>
	<li>At most <code>104</code> calls will be made to <code>add</code>.</li>
	<li>It is guaranteed that there will be at least <code>k</code> elements in the array when you search for the <code>kth</code> element.</li>
</ul>

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