find-in-mountain-array

Find in Mountain Array

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findInMountainArray

(This problem is an interactive problem.)

You may recall that an array <code>arr</code> is a mountain array if and only if:

<ul>
	<li><code>arr.length &gt;= 3</code></li>
	<li>There exists some <code>i</code> with <code>0 &lt; i &lt; arr.length - 1</code> such that:
	<ul>
		<li><code>arr[0] &lt; arr[1] &lt; ... &lt; arr[i - 1] &lt; arr[i]</code></li>
		<li><code>arr[i] &gt; arr[i + 1] &gt; ... &gt; arr[arr.length - 1]</code></li>
	</ul>
	</li>
</ul>

Given a mountain array <code>mountainArr</code>, return the minimum <code>index</code> such that <code>mountainArr.get(index) == target</code>. If such an <code>index</code> does not exist, return <code>-1</code>.

You cannot access the mountain array directly. You may only access the array using a <code>MountainArray</code> interface:

<ul>
	<li><code>MountainArray.get(k)</code> returns the element of the array at index <code>k</code> (0-indexed).</li>
	<li><code>MountainArray.length()</code> returns the length of the array.</li>
</ul>

Submissions making more than <code>100</code> calls to <code>MountainArray.get</code> will be judged Wrong Answer. Also, any solutions that attempt to circumvent the judge will result in disqualification.

&nbsp;
Example 1:

<pre>
Input: array = [1,2,3,4,5,3,1], target = 3
Output: 2
Explanation: 3 exists in the array, at index=2 and index=5. Return the minimum index, which is 2.</pre>

Example 2:

<pre>
Input: array = [0,1,2,4,2,1], target = 3
Output: -1
Explanation: 3 does not exist in <code>the array,</code> so we return -1.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>3 &lt;= mountain_arr.length() &lt;= 104</code></li>
	<li><code>0 &lt;= target &lt;= 109</code></li>
	<li><code>0 &lt;= mountain_arr.get(index) &lt;= 109</code></li>
</ul>

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