delete-nodes-and-return-forest

Delete Nodes And Return Forest

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delNodes

Given the <code>root</code> of a binary tree, each node in the tree has a distinct value.

After deleting all nodes with a value in <code>to_delete</code>, we are left with a forest (a disjoint union of trees).

Return the roots of the trees in the remaining forest. You may return the result in any order.

&nbsp;
Example 1:
<img alt="" src="https://assets.leetcode.com/uploads/2019/07/01/screen-shot-2019-07-01-at-53836-pm.png" style="width: 237px; height: 150px;" />
<pre>
Input: root = [1,2,3,4,5,6,7], to_delete = [3,5]
Output: [[1,2,null,4],[6],[7]]
</pre>

Example 2:

<pre>
Input: root = [1,2,4,null,3], to_delete = [3]
Output: [[1,2,4]]
</pre>

&nbsp;
Constraints:

<ul>
	<li>The number of nodes in the given tree is at most <code>1000</code>.</li>
	<li>Each node has a distinct value between <code>1</code> and <code>1000</code>.</li>
	<li><code>to_delete.length &lt;= 1000</code></li>
	<li><code>to_delete</code> contains distinct values between <code>1</code> and <code>1000</code>.</li>
</ul>

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