check-whether-two-strings-are-almost-equivalent

Check Whether Two Strings are Almost Equivalent

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checkAlmostEquivalent

Two strings <code>word1</code> and <code>word2</code> are considered almost equivalent if the differences between the frequencies of each letter from <code>&#39;a&#39;</code> to <code>&#39;z&#39;</code> between <code>word1</code> and <code>word2</code> is at most <code>3</code>.

Given two strings <code>word1</code> and <code>word2</code>, each of length <code>n</code>, return <code>true</code> if <code>word1</code> and <code>word2</code> are almost equivalent, or <code>false</code> otherwise.

The frequency of a letter <code>x</code> is the number of times it occurs in the string.

&nbsp;
Example 1:

<pre>
Input: word1 = &quot;aaaa&quot;, word2 = &quot;bccb&quot;
Output: false
Explanation: There are 4 &#39;a&#39;s in &quot;aaaa&quot; but 0 &#39;a&#39;s in &quot;bccb&quot;.
The difference is 4, which is more than the allowed 3.
</pre>

Example 2:

<pre>
Input: word1 = &quot;abcdeef&quot;, word2 = &quot;abaaacc&quot;
Output: true
Explanation: The differences between the frequencies of each letter in word1 and word2 are at most 3:
- &#39;a&#39; appears 1 time in word1 and 4 times in word2. The difference is 3.
- &#39;b&#39; appears 1 time in word1 and 1 time in word2. The difference is 0.
- &#39;c&#39; appears 1 time in word1 and 2 times in word2. The difference is 1.
- &#39;d&#39; appears 1 time in word1 and 0 times in word2. The difference is 1.
- &#39;e&#39; appears 2 times in word1 and 0 times in word2. The difference is 2.
- &#39;f&#39; appears 1 time in word1 and 0 times in word2. The difference is 1.
</pre>

Example 3:

<pre>
Input: word1 = &quot;cccddabba&quot;, word2 = &quot;babababab&quot;
Output: true
Explanation: The differences between the frequencies of each letter in word1 and word2 are at most 3:
- &#39;a&#39; appears 2 times in word1 and 4 times in word2. The difference is 2.
- &#39;b&#39; appears 2 times in word1 and 5 times in word2. The difference is 3.
- &#39;c&#39; appears 3 times in word1 and 0 times in word2. The difference is 3.
- &#39;d&#39; appears 2 times in word1 and 0 times in word2. The difference is 2.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>n == word1.length == word2.length</code></li>
	<li><code>1 &lt;= n &lt;= 100</code></li>
	<li><code>word1</code> and <code>word2</code> consist only of lowercase English letters.</li>
</ul>

Hash Table

String

Counting

Accenture

Accolite

Activision

Adobe

Aetion

Affinity

Affirm

Airbnb

Airtel

Akamai

Akuna Capital

Alation

Alibaba

AllinCall

alphonso

Altimetrik

Amazon

American Express

Analytics quotient

AppDynamics

Apple

AQR Capital Management LLC

Arcesium

Arista Networks

Asana

Ascend

Athenahealth

Atlassian

Audible

Avalara

Baidu

Barclays

BitGo

BlackRock

Blizzard

Bloomberg

Bolt

Booking.com

Bridgewater Associates

ByteDance

C3 IoT

Canonical

Capgemini

Capital One

Cashfree

Cisco

Citadel

Citrix

Clari

Cloudera

Code Studio

codeagon

Codenation

CoderByte

Cognizant

Cohesity

Coinbase

Commvault

Coupang

Coursera

Cruise Automation

Cryptic Studios

DailyHunt

Databricks

Dataminr

DE Shaw

Dell

Deloitte

Deutsche Bank

DiDi

Directi

Discord

Docusign

DoorDash

Drawbridge

Dropbox

Dunzo

Duolingo

eBay

edabit

Electronic Arts

Epam Systems

Epic Systems

epiFi

Evernote

Expedia

Facebook

FactSet

Fallible

Fleetx

Flipkart

ForUsAll

fourkites

Garena

GE Digital

GE Healthcare

Online Assessment

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On Campus Interview

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