cells-with-odd-values-in-a-matrix

Cells with Odd Values in a Matrix

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oddCells

There is an <code>m x n</code> matrix that is initialized to all <code>0</code>&#39;s. There is also a 2D array <code>indices</code> where each <code>indices[i] = [ri, ci]</code> represents a 0-indexed location to perform some increment operations on the matrix.

For each location <code>indices[i]</code>, do both of the following:

<ol>
	<li>Increment all the cells on row <code>ri</code>.</li>
	<li>Increment all the cells on column <code>ci</code>.</li>
</ol>

Given <code>m</code>, <code>n</code>, and <code>indices</code>, return the number of odd-valued cells in the matrix after applying the increment to all locations in <code>indices</code>.

&nbsp;
Example 1:
<img alt="" src="https://assets.leetcode.com/uploads/2019/10/30/e1.png" style="width: 600px; height: 118px;" />
<pre>
Input: m = 2, n = 3, indices = [[0,1],[1,1]]
Output: 6
Explanation: Initial matrix = [[0,0,0],[0,0,0]].
After applying first increment it becomes [[1,2,1],[0,1,0]].
The final matrix is [[1,3,1],[1,3,1]], which contains 6 odd numbers.
</pre>

Example 2:
<img alt="" src="https://assets.leetcode.com/uploads/2019/10/30/e2.png" style="width: 600px; height: 150px;" />
<pre>
Input: m = 2, n = 2, indices = [[1,1],[0,0]]
Output: 0
Explanation: Final matrix = [[2,2],[2,2]]. There are no odd numbers in the final matrix.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= m, n &lt;= 50</code></li>
	<li><code>1 &lt;= indices.length &lt;= 100</code></li>
	<li><code>0 &lt;= ri &lt; m</code></li>
	<li><code>0 &lt;= ci &lt; n</code></li>
</ul>

&nbsp;
Follow up: Could you solve this in <code>O(n + m + indices.length)</code> time with only <code>O(n + m)</code> extra space?

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