binary-prefix-divisible-by-5

Binary Prefix Divisible By 5

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prefixesDivBy5

You are given a binary array <code>nums</code> (0-indexed).

We define <code>xi</code> as the number whose binary representation is the subarray <code>nums[0..i]</code> (from most-significant-bit to least-significant-bit).

<ul>
	<li>For example, if <code>nums = [1,0,1]</code>, then <code>x0 = 1</code>, <code>x1 = 2</code>, and <code>x2 = 5</code>.</li>
</ul>

Return an array of booleans <code>answer</code> where <code>answer[i]</code> is <code>true</code> if <code>xi</code> is divisible by <code>5</code>.

&nbsp;
Example 1:

<pre>
Input: nums = [0,1,1]
Output: [true,false,false]
Explanation: The input numbers in binary are 0, 01, 011; which are 0, 1, and 3 in base-10.
Only the first number is divisible by 5, so answer[0] is true.
</pre>

Example 2:

<pre>
Input: nums = [1,1,1]
Output: [false,false,false]
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= nums.length &lt;= 105</code></li>
	<li><code>nums[i]</code> is either <code>0</code> or <code>1</code>.</li>
</ul>

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