3sum

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3Sum

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threeSum

Given an integer array nums, return all the triplets <code>[nums[i], nums[j], nums[k]]</code> such that <code>i != j</code>, <code>i != k</code>, and <code>j != k</code>, and <code>nums[i] + nums[j] + nums[k] == 0</code>.

Notice that the solution set must not contain duplicate triplets.

&nbsp;
Example 1:

<pre>
Input: nums = [-1,0,1,2,-1,-4]
Output: [[-1,-1,2],[-1,0,1]]
Explanation: 
nums[0] + nums[1] + nums[2] = (-1) + 0 + 1 = 0.
nums[1] + nums[2] + nums[4] = 0 + 1 + (-1) = 0.
nums[0] + nums[3] + nums[4] = (-1) + 2 + (-1) = 0.
The distinct triplets are [-1,0,1] and [-1,-1,2].
Notice that the order of the output and the order of the triplets does not matter.
</pre>

Example 2:

<pre>
Input: nums = [0,1,1]
Output: []
Explanation: The only possible triplet does not sum up to 0.
</pre>

Example 3:

<pre>
Input: nums = [0,0,0]
Output: [[0,0,0]]
Explanation: The only possible triplet sums up to 0.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>3 &lt;= nums.length &lt;= 3000</code></li>
	<li><code>-105 &lt;= nums[i] &lt;= 105</code></li>
</ul>

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