[Java] Simple DFS with check for adjacent characters, O(V+E) Solution - Longest Path With Different Adjacent Characters - LeetCode

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C++JavaPython3CPythonRustGoJavaScriptC#KotlinRubyTypeScriptSwiftScalaPHPElixirDartDepth-First SearchTreeGraphRecursionStringArrayHeap (Priority Queue)Topological SortBreadth-First SearchDynamic ProgrammingBinary TreeHash TableGreedyMemoizationBacktrackingQueueSortingDivide and ConquerStackMathSortBinary Search TreeIteratorHash Function