k-highest-ranked-items-within-a-price-range

java

python

python3

mysql

mssql

oraclesql

csharp

javascript

typescript

bash

swift

kotlin

dart

golang

ruby

scala

rust

racket

erlang

elixir

pythondata

postgresql

Algorithms

You are given a 0-indexed 2D integer array <code>grid</code> of size <code>m x n</code> that represents a map of the items in a shop. The integers in the grid represent the following:

<ul>
	<li><code>0</code> represents a wall that you cannot pass through.</li>
	<li><code>1</code> represents an empty cell that you can freely move to and from.</li>
	<li>All other positive integers represent the price of an item in that cell. You may also freely move to and from these item cells.</li>
</ul>

It takes <code>1</code> step to travel between adjacent grid cells.

You are also given integer arrays <code>pricing</code> and <code>start</code> where <code>pricing = [low, high]</code> and <code>start = [row, col]</code> indicates that you start at the position <code>(row, col)</code> and are interested only in items with a price in the range of <code>[low, high]</code> (inclusive). You are further given an integer <code>k</code>.

You are interested in the positions of the <code>k</code> highest-ranked items whose prices are within the given price range. The rank is determined by the first of these criteria that is different:

<ol>
	<li>Distance, defined as the length of the shortest path from the <code>start</code> (shorter distance has a higher rank).</li>
	<li>Price (lower price has a higher rank, but it must be in the price range).</li>
	<li>The row number (smaller row number has a higher rank).</li>
	<li>The column number (smaller column number has a higher rank).</li>
</ol>

Return the <code>k</code> highest-ranked items within the price range sorted by their rank (highest to lowest). If there are fewer than <code>k</code> reachable items within the price range, return all of them.

&nbsp;
Example 1:
<img alt="" src="https://assets.leetcode.com/uploads/2021/12/16/example1drawio.png" style="width: 200px; height: 151px;" />
<pre>
Input: grid = [[1,2,0,1],[1,3,0,1],[0,2,5,1]], pricing = [2,5], start = [0,0], k = 3
Output: [[0,1],[1,1],[2,1]]
Explanation: You start at (0,0).
With a price range of [2,5], we can take items from (0,1), (1,1), (2,1) and (2,2).
The ranks of these items are:
- (0,1) with distance 1
- (1,1) with distance 2
- (2,1) with distance 3
- (2,2) with distance 4
Thus, the 3 highest ranked items in the price range are (0,1), (1,1), and (2,1).
</pre>

Example 2:
<img alt="" src="https://assets.leetcode.com/uploads/2021/12/16/example2drawio1.png" style="width: 200px; height: 151px;" />
<pre>
Input: grid = [[1,2,0,1],[1,3,3,1],[0,2,5,1]], pricing = [2,3], start = [2,3], k = 2
Output: [[2,1],[1,2]]
Explanation: You start at (2,3).
With a price range of [2,3], we can take items from (0,1), (1,1), (1,2) and (2,1).
The ranks of these items are:
- (2,1) with distance 2, price 2
- (1,2) with distance 2, price 3
- (1,1) with distance 3
- (0,1) with distance 4
Thus, the 2 highest ranked items in the price range are (2,1) and (1,2).
</pre>

Example 3:
<img alt="" src="https://assets.leetcode.com/uploads/2021/12/30/example3.png" style="width: 149px; height: 150px;" />
<pre>
Input: grid = [[1,1,1],[0,0,1],[2,3,4]], pricing = [2,3], start = [0,0], k = 3
Output: [[2,1],[2,0]]
Explanation: You start at (0,0).
With a price range of [2,3], we can take items from (2,0) and (2,1). 
The ranks of these items are: 
- (2,1) with distance 5
- (2,0) with distance 6
Thus, the 2 highest ranked items in the price range are (2,1) and (2,0). 
Note that k = 3 but there are only 2 reachable items within the price range.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>m == grid.length</code></li>
	<li><code>n == grid[i].length</code></li>
	<li><code>1 &lt;= m, n &lt;= 105</code></li>
	<li><code>1 &lt;= m * n &lt;= 105</code></li>
	<li><code>0 &lt;= grid[i][j] &lt;= 105</code></li>
	<li><code>pricing.length == 2</code></li>
	<li><code>2 &lt;= low &lt;= high &lt;= 105</code></li>
	<li><code>start.length == 2</code></li>
	<li><code>0 &lt;= row &lt;= m - 1</code></li>
	<li><code>0 &lt;= col &lt;= n - 1</code></li>
	<li><code>grid[row][col] &gt; 0</code></li>
	<li><code>1 &lt;= k &lt;= m * n</code></li>
</ul>