employee-importance

Employee Importance

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getImportance

You have a data structure of employee information, including the employee&#39;s unique ID, importance value, and direct subordinates&#39; IDs.

You are given an array of employees <code>employees</code> where:

<ul>
	<li><code>employees[i].id</code> is the ID of the <code>ith</code> employee.</li>
	<li><code>employees[i].importance</code> is the importance value of the <code>ith</code> employee.</li>
	<li><code>employees[i].subordinates</code> is a list of the IDs of the direct subordinates of the <code>ith</code> employee.</li>
</ul>

Given an integer <code>id</code> that represents an employee&#39;s ID, return the total importance value of this employee and all their direct and indirect subordinates.

&nbsp;
Example 1:
<img alt="" src="https://assets.leetcode.com/uploads/2021/05/31/emp1-tree.jpg" style="width: 400px; height: 258px;" />
<pre>
Input: employees = [[1,5,[2,3]],[2,3,[]],[3,3,[]]], id = 1
Output: 11
Explanation: Employee 1 has an importance value of 5 and has two direct subordinates: employee 2 and employee 3.
They both have an importance value of 3.
Thus, the total importance value of employee 1 is 5 + 3 + 3 = 11.
</pre>

Example 2:
<img alt="" src="https://assets.leetcode.com/uploads/2021/05/31/emp2-tree.jpg" style="width: 362px; height: 361px;" />
<pre>
Input: employees = [[1,2,[5]],[5,-3,[]]], id = 5
Output: -3
Explanation: Employee 5 has an importance value of -3 and has no direct subordinates.
Thus, the total importance value of employee 5 is -3.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= employees.length &lt;= 2000</code></li>
	<li><code>1 &lt;= employees[i].id &lt;= 2000</code></li>
	<li>All <code>employees[i].id</code> are unique.</li>
	<li><code>-100 &lt;= employees[i].importance &lt;= 100</code></li>
	<li>One employee has at most one direct leader and may have several subordinates.</li>
	<li>The IDs in <code>employees[i].subordinates</code> are valid IDs.</li>
</ul>

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