couples-holding-hands

Couples Holding Hands

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minSwapsCouples

There are <code>n</code> couples sitting in <code>2n</code> seats arranged in a row and want to hold hands.

The people and seats are represented by an integer array <code>row</code> where <code>row[i]</code> is the ID of the person sitting in the <code>ith</code> seat. The couples are numbered in order, the first couple being <code>(0, 1)</code>, the second couple being <code>(2, 3)</code>, and so on with the last couple being <code>(2n - 2, 2n - 1)</code>.

Return the minimum number of swaps so that every couple is sitting side by side. A swap consists of choosing any two people, then they stand up and switch seats.

&nbsp;
Example 1:

<pre>
Input: row = [0,2,1,3]
Output: 1
Explanation: We only need to swap the second (row[1]) and third (row[2]) person.
</pre>

Example 2:

<pre>
Input: row = [3,2,0,1]
Output: 0
Explanation: All couples are already seated side by side.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>2n == row.length</code></li>
	<li><code>2 &lt;= n &lt;= 30</code></li>
	<li><code>n</code> is even.</li>
	<li><code>0 &lt;= row[i] &lt; 2n</code></li>
	<li>All the elements of <code>row</code> are unique.</li>
</ul>

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