concatenate-non-zero-digits-and-multiply-by-sum-i

java

python3

python

javascript

typescript

csharp

golang

kotlin

swift

rust

ruby

dart

scala

elixir

erlang

racket

bash

mysql

mssql

postgresql

oraclesql

pythondata

Algorithms

You are given an integer <code>n</code>.

Form a new integer <code>x</code> by concatenating all the non-zero digits of <code>n</code> in their original order. If there are no non-zero digits, <code>x = 0</code>.

Let <code>sum</code> be the sum of digits in <code>x</code>.

Return an integer representing the value of <code>x * sum</code>.

&nbsp;
Example 1:

<div class="example-block">
Input: n = 10203004

Output: 12340

Explanation:

<ul>
	<li>The non-zero digits are 1, 2, 3, and 4. Thus, <code>x = 1234</code>.</li>
	<li>The sum of digits is <code>sum = 1 + 2 + 3 + 4 = 10</code>.</li>
	<li>Therefore, the answer is <code>x * sum = 1234 * 10 = 12340</code>.</li>
</ul>
</div>

Example 2:

<div class="example-block">
Input: n = 1000

Output: 1

Explanation:

<ul>
	<li>The non-zero digit is 1, so <code>x = 1</code> and <code>sum = 1</code>.</li>
	<li>Therefore, the answer is <code>x * sum = 1 * 1 = 1</code>.</li>
</ul>
</div>

&nbsp;
Constraints:

<ul>
	<li><code>0 &lt;= n &lt;= 109</code></li>
</ul>