You are given a bitonic array nums of length n.
Split the array into two parts:
- Ascending part: from index 0 to the peak element (inclusive).
- Descending part: from the peak element to index
n - 1 (inclusive).
The peak element belongs to both parts.
Return:
- 0 if the sum of the ascending part is greater.
- 1 if the sum of the descending part is greater.
- -1 if both sums are equal.
Notes:
- A bitonic array is an array that is strictly increasing up to a single peak element and then strictly decreasing.
- An array is said to be strictly increasing if each element is strictly greater than its previous one (if exists).
- An array is said to be strictly decreasing if each element is strictly smaller than its previous one (if exists).
Example 1:
Input: nums = [1,3,2,1]
Output: 1
Explanation:
- Peak element is
nums[1] = 3
- Ascending part =
[1, 3], sum is 1 + 3 = 4
- Descending part =
[3, 2, 1], sum is 3 + 2 + 1 = 6
- Since the descending part has a larger sum, return 1.
Example 2:
Input: nums = [2,4,5,2]
Output: 0
Explanation:
- Peak element is
nums[2] = 5
- Ascending part =
[2, 4, 5], sum is 2 + 4 + 5 = 11
- Descending part =
[5, 2], sum is 5 + 2 = 7
- Since the ascending part has a larger sum, return 0.
Example 3:
Input: nums = [1,2,4,3]
Output: -1
Explanation:
- Peak element is
nums[2] = 4
- Ascending part =
[1, 2, 4], sum is 1 + 2 + 4 = 7
- Descending part =
[4, 3], sum is 4 + 3 = 7
- Since both parts have equal sums, return -1.
Constraints:
3 <= n == nums.length <= 1051 <= nums[i] <= 109nums is a bitonic array.