binary-tree-inorder-traversal

Binary Tree Inorder Traversal

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inorderTraversal

Given the <code>root</code> of a binary tree, return the inorder traversal of its nodes&#39; values.

&nbsp;
Example 1:
<img alt="" src="https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg" style="width: 125px; height: 200px;" />
<pre>
Input: root = [1,null,2,3]
Output: [1,3,2]
</pre>

Example 2:

<pre>
Input: root = []
Output: []
</pre>

Example 3:

<pre>
Input: root = [1]
Output: [1]
</pre>

&nbsp;
Constraints:

<ul>
	<li>The number of nodes in the tree is in the range <code>[0, 100]</code>.</li>
	<li><code>-100 &lt;= Node.val &lt;= 100</code></li>
</ul>

&nbsp;
Follow up: Recursive solution is trivial, could you do it iteratively?

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