angle-between-hands-of-a-clock

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Algorithms

Given two numbers, <code>hour</code> and <code>minutes</code>, return the smaller angle (in degrees) formed between the <code>hour</code> and the <code>minute</code> hand.

Answers within <code>10-5</code> of the actual value will be accepted as correct.

&nbsp;
Example 1:
<img alt="" src="https://assets.leetcode.com/uploads/2019/12/26/sample_1_1673.png" style="width: 300px; height: 296px;" />
<pre>
Input: hour = 12, minutes = 30
Output: 165
</pre>

Example 2:
<img alt="" src="https://assets.leetcode.com/uploads/2019/12/26/sample_2_1673.png" style="width: 300px; height: 301px;" />
<pre>
Input: hour = 3, minutes = 30
Output: 75
</pre>

Example 3:
<img alt="" src="https://assets.leetcode.com/uploads/2019/12/26/sample_3_1673.png" style="width: 300px; height: 301px;" />
<pre>
Input: hour = 3, minutes = 15
Output: 7.5
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= hour &lt;= 12</code></li>
	<li><code>0 &lt;= minutes &lt;= 59</code></li>
</ul>