Today's problem was a great introduction to the power of Backtracking.

Problem: Given n pairs of parentheses, generate all possible combinations of well-formed parentheses.

Approach: Instead of generating all combinations and checking validity later, we build only valid sequences:

1. Add "(" when we still have opening brackets available.
2. Add ")" only when it won't make the sequence invalid.
3. Continue recursively until a complete valid combination is formed.

🎯 Key Learning:
✅ Understanding Backtracking
✅ Building solutions recursively
✅ Pruning invalid paths early
✅ Improving recursion problem-solving skills

• Example (n = 3): ((())) (()()) (())() ()(()) ()()()