The simple cube root problem, let me find the cubic root for input x and error is less than k.  Here is a solution. I came up with the solution but forget to add float(x). So I did not get the offer. The interview did not mention what you are supposed to return. Therefore, be carful!\n\nBest luck for me next, and best luck for all of you ~~~\n\nThis solution idea is same as :https://leetcode.com/problems/sqrtx/  which is simple Newton\'s method. Love math! \n\n```python \ndef cubeRoot(x, k):\n    """\n    :type x: int\n\t:type k: float\n    :rtype: float\n    """\n    \n    temp_value = float(x)\n    res = 0\n    \n    while abs(temp_value * temp_value * temp_value - x) > k:\n        temp_value = (temp_value + x / temp_value / temp_value) / 2\n        \n    res = temp_value\n    \n    return res\n\t\n```\n

The simple cube root problem, let me find the cubic root for input x and error is less than k.  Here is a solution. I came up with the solution but forget to ad