Given a set of distinct numbers, find all of its permutations.
Input: [1,3,5]
Output: [1,3,5], [1,5,3], [3,1,5], [3,5,1], [5,1,3], [5,3,1]
Could you please help me understand why below code time complexity and space is O(n*n!) ?
class Permutations {
public static List<List<Integer>> findPermutations(int[] nums) {
List<List<Integer>> result = new ArrayList<>();
Queue<List<Integer>> permutations = new LinkedList<>();
permutations.add(new ArrayList<>());
for (int currentNumber : nums) {
// we will take all existing permutations and add the current number to create new permutations
int n = permutations.size();
for (int i = 0; i < n; i++) {
List<Integer> oldPermutation = permutations.poll();
// create a new permutation by adding the current number at every position
for (int j = 0; j <= oldPermutation.size(); j++) {
List<Integer> newPermutation = new ArrayList<Integer>(oldPermutation);
newPermutation.add(j, currentNumber);
if (newPermutation.size() == nums.length)
result.add(newPermutation);
else
permutations.add(newPermutation);
}
}
}
return result;
}
public static void main(String[] args) {
List<List<Integer>> result = Permutations.findPermutations(new int[] { 1, 3, 5 });
System.out.print("Here are all the permutations: " + result);
}
}