Implement Java's `Math.sin(x)` function which takes an input number and returns the `sin()` double value.

`sin(x)` is defined by the Taylor Series as: $$X - X^3/3! + X^5/5! - X^7/7!....$$

**Challenges**:
1. Taylor series has no end. When do you decide to terminate and return value to avoid infinite loop?
2. What is the precision to aim for return value?

**Decision**: Passed to onsite & Downleveled. Needed few hints from the interviewer to be nudged in the right direction.

Implement Java's Math.sin(x) function which takes an input number and returns the sin() double value.sin(x) is defined by the Taylor Series as: X−X3/3!+X5/5!−X7/7!....Challenges:
Taylor series has no end. When do you decide to terminate and return va

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