MakeMyTrip | Arzooo | Interview Question
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Question -> A string will be passed as an argument, if there is an embedded key present in the object, return it else return undefined.

Solution -> I firstly thought of recursion but it can be easily solved without recursion since object is already present inside the function.

/*
- Write method findPath
- Should take two params:
    - object
    - keys separated by dots as string
- Return value if it exists at that path inside the object, else return undefined
*/

var obj = {
    a: {
        b: {
            c: 12,
            j: false
        },
        k: null
    }
};

const findPath = (object, path) => {
    const arr = path.split('.');
    //console.log(arr);
    let ans = object;
    for(let x in arr){
        //console.log("path",x,arr[x]);
        if(ans[arr[x]]!==undefined){
            ans = ans[arr[x]];
        }
        else{
            ans = undefined;
            break;
        }
    }
    return ans;   
};


console.log(findPath(obj, 'a.b.c')); // 12
console.log(findPath(obj, 'a.b')); // {c: 12, j: false}
console.log(findPath(obj, 'a.b.d')); // undefined
console.log(findPath(obj, 'a.c')); // undefined
console.log(findPath(obj, 'a.b.c.d')); // undefined
console.log(findPath(obj, 'a.b.c.d.e')); // undefined
console.log(findPath(obj, 'a.b.j')); //false
console.log(findPath(obj, 'a.b.j.k')); //undefined
console.log(findPath(obj, 'a.k')); //null
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