For https://leetcode.com/explore/learn/card/linked-list/214/two-pointer-technique/1216
slow != null can be removed from the template and make code cleaner. Below is Java version, same to C++ version.
// Initialize slow & fast pointers
ListNode slow = head;
ListNode fast = head;
/**
* Change this condition to fit specific problem.
* Attention: remember to avoid null-pointer error
**/
while (slow != null && fast != null && fast.next != null) {
slow = slow.next; // move slow pointer one step each time
fast = fast.next.next; // move fast pointer two steps each time
if (slow == fast) { // change this condition to fit specific problem
return true;
}
}
return false; // change return value to fit specific problem