Simple JS solution for "Check If N and Its Double Exist"
for (let i = 0; i < arr.length; i++) {
        const n = arr[i] * 2
        for (let j = 0; j < arr.length; j++) {
            if (i !== j && n === arr[j]) {
                return true
            } 
        }           
    }
    return false
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