#### Approach #1: Build String [Accepted]

Intuition

Let's individually build the result of each string (build(S) and build(T)), then compare if they are equal.

Algorithm

To build the result of a string build(S), we'll use a stack based approach, simulating the result of each keystroke.

Complexity Analysis

• Time Complexity: , where are the lengths of S and T respectively.

• Space Complexity: .

#### Approach #2: Two Pointer [Accepted]

Intuition

When writing a character, it may or may not be part of the final string depending on how many backspace keystrokes occur in the future.

If instead we iterate through the string in reverse, then we will know how many backspace characters we have seen, and therefore whether the result includes our character.

Algorithm

Iterate through the string in reverse. If we see a backspace character, the next non-backspace character is skipped. If a character isn't skipped, it is part of the final answer.

See the comments in the code for more details.

Complexity Analysis

• Time Complexity: , where are the lengths of S and T respectively.

• Space Complexity: .

Analysis written by: @awice.